Question

A 1000kg boat is being towed by a rope that makes an angle of 20 degrees with respect to the x-axis. The boat accelerates horizontally from rest to 10 m/s in 5.0 seconds. During this time, a total drag force of 500N acts on the boat from the water. What is the tension in the rope during this time?

Answer 1

Step-by-step explanation:

acceleration of the boat a = (10 - 0) / 5 = 2 m /s²

Let tension in the rope be T

Horizontal component = T cos20

force acting on boat = T cos20 - 500

applying newton's law

T cos20 - 500 = mass x acceleration

T cos20 - 500 = 1000 x 2 = 2000

T cos20 = 2500 N .

T x .94 = 2500

T = 2660 N .