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Factor 49x^2-7^2
and please explain how

User Fatbuddha
by
4.0k points

1 Answer

5 votes

Answer:


49x^2-7^2=49(x-1)(x+1)

Explanation:

Factoring

We need to recall this property of binomials:


(a-b)(a+b)= a^2-b^2

It allows us to factor the difference between two squares as follows.


a^2-b^2=(a-b)(a+b)

The given expression is


49x^2-7^2

Comparing with the above expression:


a^2=49x^2

Taking square root:


a = 7x


b^2=7^2

Taking square root:

b=7

Factoring:


49x^2-7^2=(7x-7)(7x+7)

Now we can see each factor can be taken out the common factor 7:


49x^2-7^2=7(x-1)*7(x+1)

Multiplying:


\boxed{49x^2-7^2=49(x-1)(x+1)}

User AndrewD
by
4.5k points