Final answer:
To completely vaporize 100 grams of H2O at 100°C and 1.0 atm, 225,000 joules of heat is required.
Step-by-step explanation:
Total quantity = 100 grams
Temperature = 100C
To calculate the quantity of heat required to completely vaporize 100 grams of H2O at 100°C and 1.0 atm, we need to use the heat of vaporization and the formula:
- Mass of water (in grams) × Heat of vaporization (in joules/gram)
- Substituting the values -
- 100 g × 2250 J/g = 225,000 J
Therefore, the quantity of heat required is 225,000 joules.