Answer:
The heat of vaporization relates the amount of heat required to transform a certain phase of a certain amount of substance from liquid to gas. The heat of vaporization of substances can be expressed in terms of joules per gram or joules per mole.
ExplanaDetermine the total amount of heat, q, that is required to evaporate the given amount of water at its boiling point. For this problem, we simply apply the equation,q
=
m
Δ
H
v
a
p
where m is the mass and
Δ
H
v
a
p
is the enthalpy of vaporization of water. We use the following values:
m
=
100
g
Δ
H
v
a
p
=
2.26
k
J
/
g
We proceed with the solution.
q
=
m
Δ
H
v
a
p
=
(
100
g
)
(
2.26
k
J
/
g
)
=
226 k
j tion: