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What volume of oxygen gas is needed for the complete combustion of 40.0 liters of hydrogen gas?

User NikedLab
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1 Answer

10 votes

Answer:

2C2H6 + 7O2 ==> 4CO2 + 6H2O

When dealing with gases, it is possible to use liters and mols interchangeably.

So 4.00 L C2H6 x (7 mols O2/2 mols C2H6) = 4.00 x 7/2 = ? L O2

Step-by-step explanation:

User WReach
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