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Find three consecutive odd integers such that the sum of twice the largest and the smallest is

101.

User Craftein
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Answer:

The sum of any set of consecutive odd numbers starting with 1 is always equal to the square of the number of digits that were added together. Sum of first two odd numbers = 1 + 3 = 4 (= 2 x 2). Sum of first three odd numbers = 1 + 3 + 5 = 9 (= 3 x 3). Sum of first four odd numbers = 1 + 3 + 5 + 7 = 16 (= 4 x 4).

Explanation:


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User Huonderv
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