You would multiply top and bottom by
to go from
to
![(√(3))/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/18kau8ceig8clbxf1xo4f2wc9bplikpsm1.png)
Multiplying a square root by itself is the same as squaring the value.
So,
![√(x)*√(x) = (√(x))^2 = x, \ \ \text{ when } x \ge 0](https://img.qammunity.org/2021/formulas/mathematics/college/ftpb1iic6p5y29fa1xgkrum3mciiy517k4.png)
Which is why we're able to get rid of the square root in the denominator. The square root and squaring operation effectively cancel each other out.