Question

Find the probability of getting a doublet in a throw of a pair of dice.​

Answer 1

Question:

Find the probability of getting a doublet in a throw of a pair of dice.

Answer:

The probability is 1 out of 6.

Step-by-step explanation:

There are a total of 6 possibilities that you get a doublet, which is {1, 1}, {2, 2}, {3, 3}, {4, 4}, {5, 5}, and {6, 6}.

The total possibilities of throwing a dice are 6 possibilities for the first dice, and 6 possibilities for the second dice. Which results in a total of 6 × 6 = 36 possibilities available.

Probability = Possibilities of getting doublet ÷ Total possibilities = 6 ÷ 36 = 1 ÷ 6.

Hopefully this answer will help you.

Answer 2

There are six ways to roll 2 dice such that both dice have the same value
These are the outcomes (1,1),(2,2),(3,3),(4,4,)(5,5) and (6,6).

To find the total number of outcomes, note that there are 6 choices for the first die (values 1–6) and there are 6 choices for the second die (again values 1–6) and so by the Multiplication Principle (MP) there are 36 total outcomes from rolling two dice once.

Now we have the following:

P(getting a doublet) =
Total number of outcomes
Number of ways to get double
​
=
36
6
​
=
6
1
​


Thus, the probability of getting a doublet is
6
1
​
.