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A computer randomly puts a point inside the rectangle. What is the probability

that the point does not land in triangle T?

A computer randomly puts a point inside the rectangle. What is the probability that-example-1
User Egidi
by
8.0k points

2 Answers

4 votes

Answer:

Just took test its 7/8

Explanation:

User Axel Tetzlaff
by
8.4k points
4 votes

Answer:

87.5%

Step-by-step explanation:

The area of the entire rectangle is 8 by 6,

8x6=48 so the area is 48 units^2.

The area of the triangle is A=1/2bh

A=1/2(2)(6)

A=1(6)

A=6 units^2

6/48=0.125

0.125=12.5%

You need to find the percent it will not land in the triangle, so subtract 12.5 from 100.

100-12.5=87.5

There is an 87.5% chance it will not land in the triangle

User Enixa
by
7.0k points

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