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In AJKL, JL is extended through point L to point M, mZLJK = (2x + 2)°,

mZKLM = (82 – 16)°, and m/JKL (3x + 6)". Find mZKLM.

In AJKL, JL is extended through point L to point M, mZLJK = (2x + 2)°, mZKLM = (82 – 16)°, and-example-1

1 Answer

2 votes

Answer:

<KLM = 48 degrees

Explanation:

According to the instructions, we construct the triangle JKL and extend the side JL to point M. The information about the angles is shown in the attached image.

Recall that the addition of all internal angles of a triangle must give 180 degrees.

The angles we need to complete the addition is angle <JLK, which happens to be the supplementary angles to angle <KLM

Therefore <JLK = 180 - (8 x - 16) = 180 - 8 x + 16 = 196 - 8 x

The we can now solve for "x" in the equation of addition of internal angles of a triangle:

(2 x + 2) + (3 x + 6) + (196 - 8 x) = 180

Combining like terms on the left

- 3 x + 204 = 180

subtracting 204 from both sides:

- 3 x = 180 - 204

- 3 x = - 24

divide both sides by "-3" to isolate x

x = - 24 / (-3)

x = 8 degrees

Now that we know "x", we can find the measure of angle <KLM via its formula:

<KLM = 8 x - 16 = 8 (8) - 16 = 48 degrees

In AJKL, JL is extended through point L to point M, mZLJK = (2x + 2)°, mZKLM = (82 – 16)°, and-example-1
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