409,536 views
18 votes
18 votes
If x-y=5 and xy=4,find the value of x3-y3​

User Thomas Hofmann
by
2.4k points

1 Answer

11 votes
11 votes


\text{Given that,} ~ x-y = 5~ \text{amd}~ xy = 4\\\\\text{Now,}\\\\x^3 -y^3\\\\=(x-y)(x^2 +xy+y^2)\\\\=(x-y)[(x-y)^2 +2xy +xy]\\\\=(x-y)[(x-y)^2 +3xy]\\\\=5(5^2+3\cdot 4)\\\\=5(25+12)\\\\=5(37)\\\\=185

User Amedina
by
2.5k points