Question

On a unit circle, what is tan for coordinates (-√2/2, √2/2)?

a.) -1
b.) -√2/2
c.) 1
d.) √2/2
e.)√2​

Answer 1

your correct answer cuz is

A

Explanation:

Answer 2

A

Explanation:

Remember that tangent is the ratio of sine over cosine.

`\tan(\theta)=(\sin(\theta))/(\cos(\theta))`

In the unit circle:

• Sine refers to the y-coordinate.
• Cosine refers to the x-coordinate.

Our x-coordinate is -√2/2 and our y-coordinate is √2/2.

So, substitute -√2/2 for cosine and √2/2 for sine. This yields:

`\tan(\theta)=(\sqrt2/2)/(-\sqrt2/2)`

Since the numerator and the denominator are the same save for a negative, we can cancel them:

`\tan(\theta)=-1`

So, our answer is A.