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In ΔFGH, the measure of ∠H=90°, the measure of ∠F=18°, and GH = 9.4 feet. Find the length of HF to the nearest tenth of a foot.

1 Answer

5 votes

Answer:

28.9

Explanation:

tan (18) = 9.4/x times x

x times tan(18) = 9.4 / tan(18)

tan(18)

crosses out.

On a calculator do 9.4/

tan(18).

x = 28.9

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