Question

Give the equation of the line going through the point (0, -3) and perpendicular to 4x - 8y = 16.

Please answer quickly. It's due tomorrow

Answer 1

y=-2x-3

Explanation:

The equation of the line in the slope-intercept form is y=x2−2.

The slope of the perpendicular line is negative inverse: m=−2.

So, the equation of the perpendicular line is y=−2x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−2)⋅(0)+a.

Thus, a=−3.

Therefore, the equation of the line is y=−2x−3.

Answer: y=−2x−3.

Answer 2

y=-1/4x+3

Explanation:

put it into y-y1=m(x-x1) form, which gives you y+3=-1/4x(x+0)

(side note: we change the y- to a y+ becuase the y in the point in negative. another side note, the slope is -1/4x because perpendicular slopes are opposite, in this case 4x (or 4/1x) is the opposite of -1/4 x)

then remove the parenthesis. y+3=-1/4x

then isolate y and balance the equation.

y+3-3=-1/4x-3

this gives you the answer of y=-1/4x-3.