Question

Write an equation of the line

that passes through (6, -1)
and is perpendicular to
y = 3x + 2.

Answer 1

Explanation:

Perpendicular lines have the relationship that their slope is the negative reciprocal of the other's.

in this case, the other line's slope is
`(-1)/(3)`

we can use (6, -1) to solve the rest

`y = mx + b\\y = (-x)/(3) + b\\-1 = (-6)/(3)+ b\\-1 = -2 + b\\b = 1\\y = (-1)/(3) (x) + 1`