We know 4² = 16 , 4¹= 4
In this case we have :-
![{4}^(x) = 14](https://img.qammunity.org/2023/formulas/mathematics/college/8bbmnpa372vurm6t65a7nkqy2isla7e0e7.png)
and we have to find the value of x
14 is less than 16 so x will be less than 2
14 is greater than 4 so x will be greater than 1
we can find the value of
![{4}^(1.5) = {4}^{ (3)/(2) } \\ { (√(4)) }^(3) = {2}^(3) = 8](https://img.qammunity.org/2023/formulas/mathematics/college/j1d6rs3mq13lo6up4uqhhzsai8ibuea27i.png)
so we can say 14 is much larger than 8 which means x will be much larger than 1.5
so according to above ideas we can say our answer is 2nd option which is 1.9037 is our answer
![x \approx1.9037](https://img.qammunity.org/2023/formulas/mathematics/college/iijm8fyp48qdhg1mpzqvvwrxnho8c7bpog.png)