Answer:
In the figure,
AC is the diameter of circle with centre O
∠DAC=37
o
AD || BC
∠ACB=∠DAC (Alternate angles)
Hence,
x=37
o
In Δ ABC,
∠B=90
o
(angle in semicircle)
By angle sum property of triangle, we get,
∠x+∠y+∠B=180
o
37
o
+∠y+90
o
=180
o
∠y=180
o
−127
o
We get,
∠y=53
o
Explanation: