Question

X varies inversely as y², and x = 6 when y = 8. Find x when y = 2.

Answer 1

x=96

Explanation:

Since x varies inversely as
`y^(2)`, x*
`y^(2)` = k

sub x=6, y=8 into x
`y^(2)` = k => 6*64 = k => k= 384

so when y =2, x = 384/ (
`2^(2)`) = 384/4 = 96

Done :)