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O is the centre of the circle find the size of each angle ​

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Answer:

In the figure,

AC is the diameter of circle with centre O

∠DAC=37

o

AD || BC

∠ACB=∠DAC (Alternate angles)

Hence,

x=37

o

In Δ ABC,

∠B=90

o

(angle in semicircle)

By angle sum property of triangle, we get,

∠x+∠y+∠B=180

o

37

o

+∠y+90

o

=180

o

∠y=180

o

−127

o

We get,

∠y=53

o

Explanation:

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