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The width of a rectangle is 3 less than twice the length, x. If the perimeter of the rectangle is 43 feet, find the dimensions.

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Answer:

Explanation:

we're given that


W = 2X - 3\\P = 43\\

the perimeter can be defined as


P = 2X + 2W \\so\\43 = 2X + 2(2X - 3)\\43 = 2X + 4X - 6\\6X = 49\\X = (49)/(6)\\ W = 2X - 3\\W = 2(49/6) - 3\\W = 49/3 - 9/3 = (40)/(3)

The rectangle is


(49)/(6) by (40)/(3) feet

User Thibaultbl
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