Wavelength of election having kinetic energy of 400 ev.
Answer:
613.5 pm
Step-by-step explanation:
We know that de Broglie wavelength of an electron :
λ = 1.227 / √E nm
λ = 1.227 / √400 nm
λ = 1.227 / 20 nm
λ = 0.6135 nm
λ = 0.6135 x 10⁻⁹ m
λ = 613.5 x 10⁻¹² m
λ = 613.5 pm
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