Answer:
10. Butanoic acid
11. Methylpropanoate
Step-by-step explanation:
In this case first you need to identify the functional group,secondly identify the longest chain that contains the particular functional group:
10. The functional group for this compound is a carboxylic acid due to the "CHO2" group..we have four carbons which makes the parent chain to be butane.since it's acarboxylic acid we replace the "e" at the end to "oic acid".
11. The functional group is ester "RCOOR".For the ester the longest chain is counted from the part of the carboxylic acid which in this case is a propane,and the part from the alcohol becomes a substituent. With esters you replace the "e" at the end of the parent name to "oate". When you write it down you begin with the substituent in this case "methyl" and the rest follows...
hope it is clear enough