Question

A baseball rolls off a 1.20 m high desk and strikes the floor 0.50m away from the base of the desk. how fast was the ball rolling?

Answer 1

1.01 m/s

Explanation:

a = g = Acceleration due to gravity =
`9.81\ \text{m/s}^2`

t = Time

`s_y` = Displacement in y direction = 1.2 m

`s_x` = Displacement in x direction = 0.5 m

`v_x` = Velocity in x direction

Displacement in y direction is given by

`s_y=u_yt+(1)/(2)at^2\\\Rightarrow t=\sqrt{(2s_y)/(a)}\\\Rightarrow t=\sqrt{(2* 1.2)/(9.81)\\\Rightarrow t=0.4946\ \text{s}`

`s_x=v_xt\\\Rightarrow v_x=(s_x)/(t)\\\Rightarrow v_x=(0.5)/(0.4946)\\\Rightarrow v_x=1.01\ \text{m/s}`

The ball was rolling with a speed of 1.01 m/s.