Question

`\log _ { 5 } ( 2 m + 5 ) = 3log5​(2m+5)=3`

solution needed
with briefly explained​

Answer 1

m = 60

Explanation:

log is another way to write an exponent.

Example:

exponent form:

7^2 = 49

log form:

log_7 (49) = 2



In your question, we need to change to exponent form, from log form.

log_5 (2m+5)=3

5 is the base. 3 is the exponent.

Now it can be solved.

5^3 = 2m+5

125 = 2m + 5

120 = 2m

60 = m