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Construct an isosceles triangle ABC in which AB=AC = 9 cm and BÂC = 45°. Measure ABC and BC​

1 Answer

9 votes

Answer:

m∠ABC = 67.5°

BC = =6.888301782572 cm

Explanation:

ABC is an isosceles triangle

Then

m∠ABC = m∠ACB

The sum of the interior angles of a triangle is equal to 180°

Then

m∠ABC + m∠ACB + m∠BAC = 180°

Then

m∠ABC + m∠ACB + 45 = 180°

Then

2 × m∠ABC = 180°

Then

m∠ABC = (180−45)÷ 2 = 67.5°

Law of SIN :


(9)/(\sin \left( 67.5\right) ) =(BC)/(\sin \left( 45\right) )


BC=(9)/(\sin \left( 67.5\right) ) * \sin \left( 45\right) ==6.888301782572

Construct an isosceles triangle ABC in which AB=AC = 9 cm and BÂC = 45°. Measure ABC-example-1
User Gert Kommer
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