Question

1. If 150 grams of water is to be heated from 15.0°C to 100°C to make a

cup of tea, how much heat must be added? The specific heat of water is
4.18 J/gºC *
Your answer

Answer 1

You must add 53,295 J.

Step-by-step explanation:

Calorimetry is the measure of the amount of heat that a body gives up or absorbs in the course of a physical or chemical process.

When the heat added or removed from a substance causes a change in temperature in it, it is called sensible heat. In other words, sensible heat is the amount of heat absorbed or released by a substance when a change in temperature occurs, without a change in its state. Its mathematical expression is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

• Q=?
• c= 4.18
  `(J)/(g*C)`
• m=150 g
• ΔT= Tfinal - Tinitial= 100 °C - 15 °C= 85 °C

Replacing:

`Q= 4.18(J)/(g*C)*150 g*85 C`

Solving:

Q= 53,295 J

You must add 53,295 J.