Question

A body which is uniformly decelerated comes to rest in 5s after travelling of 10m. What is its initial velocity a distance​

Answer 1

4 m/s

Step-by-step explanation:

v=u+ at and v^2=u^2+2as.

It is given that v=0,t=5 s and s=10 m.

⇒0=u+5a and 0=u^2+20a.

⇒a=−u/5 and a=−u^2/20.

⇒u/5 = u^2/20⇒u=4 m/s.

⇒ The initial velocity is 4 m/s.