Question

A stone is dropped off

the edge of a cliff, and it falls for 4.8s before striking
bottom. Approximately how far above the bottom is
the cliff edge, assuming zero air resistance?

Answer 1

y=(1/2)at^2

y=(1/2)(9.8 m/s/s)(4.8 s)^2

y=60.025 m

Explanation:

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