Question

Write the equation of a line perpendicular to 5x+3y=9 and passes through the point (-10,4).

Answer 1

y=3/5x+10

Step-by-step explanation:

Step-by-step explanation:

first convert to slope intercept form y=mx+b, 5x+3y=9 that will be y=-5/3x+3, to be perpendicular, the slope has to be an opposite reciprocal so -5/3x has to be 3/5x, then pass through the point (-10,4), the equation will be y=3/5x+10

Answer 2

y=3/5x+10

Step-by-step explanation:

first convert to slope intercept form y=mx+b, 5x+3y=9 that will be y=-5/3x+3, to be perpendicular, the slope has to be an opposite reciprocal so -5/3x has to be 3/5x, then pass through the point (-10,4), the equation will be y=3/5x+10