Question

Lim x→∞ √x²+x(2a+2b)+4ab-x

notice : all coefficients and variables are in the root
AND IF YOU CAN'T ANSWER, DON'T ANSWER THIS QUESTION!!!!!​
( WITH THE STEPS!)

Answer 1

`\lim \limits_(x \to \infty) √(x^2 +x(2a+2b) +4ab-x)\\\\\\=\lim \limits_(x \to \infty) \sqrt{x^2 \left( 1 + (2a+2b)/(x)+ (4ab)/(x^2) - \frac 1{x} \right)}\\\\\\=\sqrt{\lim \limits_(x \to \infty) x^2 \cdot \lim \limits_(x \to \infty) \left( 1 + (2a+2b)/(x)+ (4ab)/(x^2) - \frac 1{x} \right)}}\\\\\\=√( \infty \cdot (1+0+0-0))\\\\=√( \infty \cdot 1)\\\\=\infty`