Question

Please solve the problem

I want whole process​

Answer 1

1

Explanation:

Solving :

⇒
`(x^(p(q-r)) )/(x^(q(p-r)) )` ÷
`((x^(q) )/(x^(p) ))^(r)`

⇒
`(x^(p(q-r)) )/(x^(q(p-r)) )` ÷
`[ ({x^(q-p) })^(r)| or| x^(r(q-p)) ]`

⇒
`{x}^(pq-pr-qp+qr)` ÷
`x^(rq-rp)`

⇒
`x^(pq-pq+qr-qr+pr-pr)`

⇒ x⁰

⇒ 1

Answer 2

1

Explanation:

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⠀⠀⠀⠀□ Question

`\Large \frac{ {x}^(p(q - r)) }{ {x}^(q(p - r)) } / {( \frac{ {x}^(q) }{{x}^(p) } })^(r)`

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⠀⠀⠀⠀■ Solution

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• Multiplying the power

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`\sf \Large{ \frac{ {x}^(pq - pr) }{ {x}^(pq - qr) } } / \frac{ {x}^(qr) }{ {x}^(pr) }`

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• Changing ÷ sign into × by doing reciprocal

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`\sf\Large{ \frac{ {x}^(pq - pr) }{ {x}^(pq - qr) } } * \frac{ {x}^(pr) }{ {x}^(qr) }`

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• As the base(x) is same, if the value is multipying so the power will add, if the value is dividing so the power will subtract.

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`\sf {x}^(pq - pr - pq + qr) * {x}^(pr - qr) \\ \\ \sf {x}^(qr - pr) * {x}^(pr - qr) \\ \\ \sf {x}^(qr - qr + pr - pr)`

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• If the power of any value become 0,so it's value is always equal to 1

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`\sf \Large{ {x}^(0) } \\ \\ \boxed {\large {\rightarrow1 }}`