Answer:
You can get to the answer in two steps:
calculate: 3.40⋅1022 atoms = x mol ?
using Avogadro's constant.
calculate: x mol = ? grams,
using the atomic mass of Helium.
Step 1
Avogadro's constant says that 1 mole of any atom contains 6.022⋅1023 atoms. In this case you have 3.40⋅1022 atoms:
3.40⋅1022atoms6.022⋅1023atomsmol = 5.65⋅10−2mol
Step 2
The atomic mass of helium (He) will give you the weight of one mole of this molecule: 1 mol = 4.00 gram:
4.00gmol⋅5.65⋅10−2mol = 0.226g
So the 3.40⋅1022 helium atoms weigh 0.226 gram.