18.4k views
0 votes
We roll two dice. Find the conditional probability that at least one of the numbers is even, given that the sum is 8.

User Demir
by
5.6k points

1 Answer

3 votes

Answer:

0.599 or 0.6

Explanation:

We will be using the alphabets M and N in this solution.

Let M be that one of the number is even

Let N be that the sum is 8

The sample space of these two dice when rolled is 36

Probability of 8 and even numbers is (4,4),(6,2),(2,6)

= 3/36 = 0.08333

Probability of sum of 8 is (4,4),(5,3)(3,5),(6,2),(2,6)

= 5/36 = 0.1389

P(M|N) = 0.08333/0.1389

= 0.599

Approximately 0.6

User Timathon
by
4.9k points