Question

A charged particle is injected at 109 m/s into a 0.0691‑T uniform magnetic field perpendicularly to the field. The diameter of its orbit is measured and found to be 0.0427 m. What is the charge–to–mass ratio of this particle?

Answer 1

We know, radius of the orbit is given by :

`r=(mv)/(qB)`

So, ratio is given by :

`(q)/(m)=(v)/(Br)\\\\(q)/(m)=(109\ m/s)/(0.0691 \ T * 0.0427\ m)\\\\(q)/(m)=36942.01 \ C/kg\\\\(q)/(m)=3.69* 10^(4)\ C/kg`

Therefore, the charge–to–mass ratio of this particle is
`3.69* 10^(4)\ C/kg` .

Hence, this is the required solution.