Question

A mischievous cat sees a flowerpot sitting at rest on a windowsill. If it takes 1.2 s for the flowerpot to fall from the window, how high up was the window?

Answer 1

Given that,

Initial speed of a cat is 0 because it was at rest.

If it takes 1.2 s for the flowerpot to fall from the window, we need to find the height reached by the cat.

Using second equation of motion to find it as follows :

`d=ut+(1)/(2)at^2`

Put u = 0 and a = g

`d=(1)/(2)gt^2\\\\d=(1)/(2)* 9.8* (1.2)^2\\\\d=7.05\ m`

So, it will move to a height of 7.05 m.