Question

Two pendulum bobs of unequal mass are suspended from the same fixed point by strings of equal length. The lighter bob is drawn aside and then released so that it collides with the other bob on reaching the vertical position. The collision is elastic. What quantities are conserved in the collision?

Answer 1

"Both kinetic energy and angular moment of the system" is the correct solution.

Step-by-step explanation:

The kinetic energy is:

`KE=(1)/(2)m_(1)v_(1)^2 + (1)/(2)m_(2)v_(2)^2`

Its conversion is:

⇒
`(KE)_(1)=(KE)_(f)`

Angular momentum is:

`L=I_(1)\omega_(1)+I_(2)\omega_(2)`

Its conversion is:

⇒
`L_(i)=L_(f)`

So that both "KE" and "L" of the system conserved.