Question

A sample of an ideal gas has a volume of 2.29 L at 285 K and 1.12 atm. Calculate the pressure when the volume is 1.33 L and the temperature is 302 K.

Answer 1

`P_2=2.04atm`

Step-by-step explanation:

Hello.

In this case, by using the combined ideal gas law, we can identify the change in pressure, temperature an volume as shown below:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

In such a way, since we are asked to compute the final pressure, P2, we proceed as follows:

`P_2=(P_1V_1T_2)/(T_1V_2) \\\\P_2=(1.12atm*2.29L*302K)/(285K*1.33L)\\ \\P_2=2.04atm`

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