Question

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A rope has a density and thickness such that a 3.25-centimeter-long segment of it weighs 61.40 grams. There are 28.3495

grams in an ounce and 2.54 centimeters in an inch. How many ounces would a 19.45 inch length of the same rope weigh?

5.10 oz

b. 11.49 OZ

32.92 oz

53.90 OZ

a

C.

d.

Please select the best answer from the choices provided

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с

D

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Answer 1

c

Step-by-step explanation:

Answer 2

A 19.45-inch-long segment of the same rope would weigh 32.92 ounces.

Step-by-step explanation:

You know that:

• 3.25 cm length of rope weighs 61.40 grams .
• There are 28.3495 grams in an ounce .
• There are 2.54 centimeters in an inch.

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), knowing the values ​​a, b and c and x being the unknown, we must apply the direct rule of three as follows:

a ⇒ b

c ⇒ x

So
`x=(c*b)/(a)`

To find the number of ounces a 19.45-inch length of the same string would weigh, you apply the following rules of three:

• If there are 2.54 centimeters in 1 inch, how many centimeters are there in 19.45 inch?

`centimeters=(19.45 inch*2.54 centimeters)/(1 inch)`

centimeters=49.403

• Now, if 3.25 centimeters long it weighs 61.40 grams, then 49.403 centimeters long, how many grams does it weigh?

`grams=(49.403 centimeters*61.40 grams)/(3.25 centimeters)`

grams= 933.34

• Finally, if there are 28.3495 grams in 1 ounce, in 933.34 grams how many ounces are there?

`ounces=(933.34 grams*1ounce)/(28.3495 grams)`

ounces= 32.92

A 19.45-inch-long segment of the same rope would weigh 32.92 ounces.