Answer:
See full explanation.
Step-by-step explanation:
Hello.
In this case, since we apply the law of mass action in order to write the equilibrium expression for each chemical reaction, we proceed as follows:
a. The reaction is:
![2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)](https://img.qammunity.org/2021/formulas/chemistry/college/5bbnf4xv3d1evocmr2x1ryc1gr0i6l5gtc.png)
And the equilibrium expression:
![Kc=([CO_2][CF_4])/([COF_2]^2)](https://img.qammunity.org/2021/formulas/chemistry/college/rrthqwx8wn9a3kam6c6s4qwora8mksr62s.png)
Since all the species are in gaseous phase they are included on the equilibrium expression.
b. The reaction is:
![Cu(s)+Ag^+(aq)\rightleftharpoons Ag(s)+Cu^(2+)(aq)](https://img.qammunity.org/2021/formulas/chemistry/college/jo8jxo2dhlwv0xq31j3w907zc1ikd80luf.png)
And the equilibrium expression:
![Kc=(Cu^(2+))/(Ag^+)](https://img.qammunity.org/2021/formulas/chemistry/college/d3lzmi50jjb8zrssahenmv57brzwd8dj34.png)
Since only copper (II) ions and silver (I) ions are in aqueous phase.
c. The reaction is redox and it turns out:
![(S_2O_8)^(2-)+Fe^(2+)\rightleftharpoons Fe^(3+)+(SO_4)^(2-)\\\\S_2^(7+)+2e^-\rightarrow 2S^(6+)\\\\2* (Fe^(2+)\rightarrow Fe^(3+)+1e^-)\\\\\\(S_2O_8)^(2-)(aq)+2Fe^(2+)(aq)\rightleftharpoons 2Fe^(3+)(aq)+2(SO_4)^(2-)(aq)](https://img.qammunity.org/2021/formulas/chemistry/college/wds31z84a2mcwxrxgjsmw97i93ewrkydkm.png)
And the equilibrium expression:
![Kc=([Fe^(3+)]^2[(SO_4)^(2-)]^2)/([(S_2O_8)^(2-)][Fe^(2+)]^2)](https://img.qammunity.org/2021/formulas/chemistry/college/7yiqis92g5n8ds89xughkn4jdgntkty16w.png)
Since all the species are in aqueous phase.