Question

What is the percent m/m concentration of an aqueous solution of sodium nitrate in which there are 24.34 grams of solute in 138.87 grams of solvent

Answer 1

14.9%m/m

Step-by-step explanation:

The percent m/m concentration of a solution (%m/m) indicates the grams of solute there are in 100 g of solution. It can be calculated as follows:

`%m/m= (mass of solute (g))/(mass of solution(g)) x 100`%m/m= mass of solute(g)/mass of solution(g) x 100

As the solution is composed by solute + solvent, the mathematical expression can be transformed in:

`%m/m= (mass of solute (g))/(mass of solution(g)) x 100`%m/m= mass of solute(g)/(mass of solute + mass of solvent (g) )x 100

= 24.34 g
`%m/m= (mass of solute (g))/(mass of solution(g)) x 100`/(24.34 g + 138.87 g) x 100

= 24.34 g/(163.21 g) x 100

= 14.9%

`%m/m= (mass of solute (g))/(mass of solution) x 100 = (mass of solute (g))/(mass of solute (g) + mass of solvent (g))`