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& this one, please and thank you!!
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14 votes
& this one, please and thank you!!

& this one, please and thank you!!-example-1
User Parttimeturtle
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6 votes


\text{Given that,} ~ p(x) = x^2 -5~ \text{and}~ h(x) = √(x+5)\\\\(p\circ h)(x)\\\\=p(h(x))\\\\=p\left( √(x+5) \right)\\\\=\left( √(x+5) \right)^2 -5\\\\=x +5-5\\\\=x

User Rafael De Leon
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