Answer:
v = 42.28 m/s
Step-by-step explanation:
It is given that,
The horizontal speed of a baseball,

The pitcher throws the baseball from a height of 1.25 meters, h = 1.25 m
Firstly finding t i.e. the stone takes to reach the ground. Using second equation of motion as follows :

a = -g and u = 0

Vertical component of the velocity is :

Resultant velocity,

So, the resultant velocity of the ball before it hits the ground is 42.28 m/s.