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What is the minimum value of the function 3x^2 -4x +8
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What is the minimum value of the function 3x^2 -4x +8

User Rambalac
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1 Answer

7 votes

Explanation:

f(x)=3x²-4x+8

f(1)=(3*1)²-4(1)+8

f(1)=3²-4+8

f(1)=9-4+8 or using BODMAS

f(1)=5+8 or f(1)=9-12

f(1)=13 or f(1)=-3

User Starikoff
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