Answer:
"115200 and 460800" is the correct approach.
Step-by-step explanation:
Total Bytes = 98 Data Bytes + 2 extra label bytes for every 10ms
= 100 bytes (every 10m)
Rate of data for every second will be:
=
![(100* 8)/(10* 10^(-3))](https://img.qammunity.org/2021/formulas/computers-and-technology/college/898fxp78dehyvtaoaqpy6ghep3bjwgqfr0.png)
=
![(800)/(0.01)](https://img.qammunity.org/2021/formulas/computers-and-technology/college/hwmtwyn9ef8thayqpd50flxfeu0ngzdsyq.png)
=
![80000](https://img.qammunity.org/2021/formulas/computers-and-technology/college/ikjfjcqvbyvwrowzvoxfvrb1dx1if757qs.png)
- The minimum baud rate required seems to be 80000.
- It is appropriate to be anything higher than 80000.
Consequently, the 115200 as well as 460800 baud rates seems to be appropriate.