If a volleyball accelerates towards the ground at 10m/s/s and it takes 1.6 seconds to hit the ground, how tall is the building

Question

asked Nov 8, 2021 217k views

1 Answer

Darren Taylor · Answer 1 · 2021-11-13T17:00:26+0000

Answer:

Distance, S = 12.8m

Step-by-step explanation:

Given the following data;

Acceleration = 10

Time = 1.6

Initial velocity = 0

To solve for acceleration, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^(2)$

Substituting the values into the equation;

$S = 0(1.6) + \frac {1}{2}*10*(1.6)^(2)$

S = 5 *2.56

Distance, S = 12.8m

Therefore, the height of the building is 12.8 meters.