Question

A shopkeper purchased 60 articles at ₹ 150 each. He sold one-third of them at a loss

of 6%.At what price each must he sell the remaining so as to to gain 10% on the whole deal.​

Answer 1

→ 11(2 + y) + 11y

→ 22 + 11y + 11y = 154

→ 22y + 22 = 154

→ 22y = 154 - 22

→ 22y = 132

→ y = 132/22

→ y = 6

Explanation:

Answer 2

Given:

Total number of articles = 60

CP of each article = Rs. 150

Find:

Price at which he sell the remaining so as to to gain 10% on the whole deal.​

Solution:

CP of 60 articles = 150 * 60 = Rs. 9000

1/3 of the articles are sold at Loss of 6%.

1/3 of articles = 1/3 * 60 = 20

⟹ CP of 20 articles = 20 * 150 = Rs. 3000

We know that,

SP = (100 - loss%)/100 * CP

⟹ SP of 20 articles = (100 - 6)/100 * 3000

⟹ SP of 20 articles = 94 * 30

⟹ SP of 20 articles = Rs. 2820

Also given that,

Total gain% = 10%

Gain% = Gain/CP * 100

⟹ 10 = Gain/9000 * 100

⟹ 10 * 9000 * 1/100 = Gain

⟹ Rs. 900 = Gain

We know,

Gain = Total SP - Total CP.

We have:

Total SP = SP of 20 articles + SP of 40 articles.

Total CP = CP of 60 articles = 9000.

So,

⟹ 900 = 2820 + SP of 40 articles - 9000

⟹ 900 - 2820 + 9000 = SP of 40 articles

⟹ Rs. 7080 = SP of 40 articles

∴ The remaining articles should be sold for Rs. 7080 to gain 10% on the whole transaction.

I hope it will help you.

Regards.