Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

Length be x

width be x-5

So

Area=Length×Breadth

• x(x-5)=750

Or

If x turned y

• y(y-5)=750
• 750-y(y-5)=0

Option C

Option A can be true as per commutatI've property

• y²-5y=750

Option B is true

Answer 2

y² - 5y = 750

750 - y(y - 5) = 0

(y + 25)(y - 30) = 0

Explanation:

Formula

Area of a rectangle = length × width

Given:

• y = length of the room
• (y - 5) = width of the room
• 750 ft² = area of the room

Substituting the given values into the formula and rearranging in different way:

Equation 1

⇒ 750 = y(y - 5)

⇒ y(y - 5) = 750

⇒ y² - 5y = 750

Equation 2

⇒ 750 = y(y - 5)

⇒ 750 - y(y - 5) = 0

Equation 3

⇒ 750 = y(y - 5)

⇒ y(y - 5) - 750 = 0

⇒ y² - 5y - 750 = 0

⇒ y² - 30y + 25y - 750 = 0

⇒ y(y - 30) + 25(y - 30) = 0

⇒ (y + 25)(y - 30) = 0