Question

Given the equation: 3x − 4y = 8,

a) write an equation of a line parallel that passes through the point (-16, 4).

b) write an equation of a line perpendicular that passes through the point (9, -7).

Answer 1

use slope intercept formula

y=Mx +b

Explanation:

3X-4Y=8

3X-8 = 4Y

y = 3/4x-2

our new equation just needs to have the same slope M= 3/4

y-y1=M(x-x1)

y-4=3/4(x-(-16))

y=3/4x+12+4

y=3/4x+16 answer a

for a perpendicular line.. just take the inverse of the slope... and change the sign. so now our slope is - 4/3

plug in our new point (9,-7)

y-(-7) = -4/3(x-9)

y+7=-4/3x+12

y= -4/3x +5 answer b