Answer: Acceleration = 4 m/s^2
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Work Shown:
The values we're working with are
![v_i = 0 = \text{ initial velocity}\\\\v_f = 16 = \text{ final velocity}\\\\t = 4 = \text{ change in time}\\\\a = \text{ unknown } = \text{ acceleration}\\\\](https://img.qammunity.org/2021/formulas/physics/high-school/4279gyhll9lpqbflcprvdfly6wgwtqywpl.png)
We'll plug those into the kinematics formula below to solve for 'a'
![v_f = v_i + a*t\\\\16 = 0 + a*4\\\\16 = 4a\\\\4a = 16\\\\a = (16)/(4)\\\\a = 4\\\\](https://img.qammunity.org/2021/formulas/physics/high-school/w8kqyscjvon2mfmhquni8ap24izf81khiu.png)
Joe's acceleration is 4 m/s^2
This means that every second, Joe's velocity is increasing by 4 m/s.
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To check our answer, we can see that
Time 0 = Velocity 0
Time 1 = Velocity 4
Time 2 = Velocity 8
Time 3 = Velocity 12
Time 4 = Velocity 16
This confirms our answer.