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What is the solution to this system of equations? 2x + 2y = 8 and 4x + 3y = 16

User Polygnome
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1 Answer

6 votes

Answer:

y=0, x=4

Explanation:

2x+2y=8 --- (1)

4x+3y=16 --- (2)

Multiply the coefficient of x in equation (1) across the variables in equation (2), and multiply the coefficients of x in equation (2) across the variables in equation (1).

8x+8y=32 ---- (3)

8x+6y=32 ---- (4)

Subtract equation (3) from (4)

2y=0, y=0/2, y=0.

Substitute the solution for y=0 into equation (1)

2x+2(0)=8

2x=8

x=4

User CMR
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